Place a slab by drawing 2-D boundaries - Intergraph Smart 3D - Help

Intergraph Smart 3D Civil

Language
English
Product
Intergraph Smart 3D
Subproduct
Civil
Search by Category
Help
Smart 3D Version
12 (2018)
  1. Click Place Slabs Command on the vertical toolbar.

  2. Define a plane for the slab.

    Define Plane as Coincident
    Define Plane using Offset from Plane
    Define Plane using Angle to Plane
    Define Plane using Vector and Point
    Define Plane using Three Points

  3. Click Accept .

  4. Click Add References to Sketch 2D on the Place Slab Ribbon.

  5. Select objects in the model that you want to see when drawing the slab boundaries in the 2-D environment.

  6. Click Draw .

    The 2D sketch orientation is based on the active coordinate system as defined in the PinPoint Command .

  7. In the 2-D environment, draw the boundaries of the slab. The boundaries that you draw must be closed shape.

  8. In the 2-D environment, click Close .

  9. Click Accept .

  10. Set the slab system, type, priority, face position, and other properties.

  11. Click Finish.

For slabs and walls defined in the sketch 2-D environment, Smart 3D removes any constraints external to the defining group when you:

  • Copy a slab or wall. The original slab or wall will still have the constraints; however, the newly created copy of the slab or wall will not have the external constraints.

  • Move a slab or wall. All external constraints are removed from the slab or wall.

  • Rotate a slab or wall. All external constraints are removed from the slab or wall.

The defining group is the lines (or other shapes) that you place in the sketch 2-D environment that defines the actual slab or wall. An example of an external to the group constraint might be an edge of a Slab XZY offset from the edge of Slab 123. The constraint is between two different slabs (defined by two different groups) so it is removed. An example of an internal to the group constraint that is not removed might be one slab side constrained to be parallel to the opposite side. In this case both sides belong to the same slab, and hence the same group, and the constraint is therefore not removed.